@@ -52,7 +52,7 @@ The example grammar in `ast/parser.lalrpop` covers a minimal subset of Rust, suf
...
@@ -52,7 +52,7 @@ The example grammar in `ast/parser.lalrpop` covers a minimal subset of Rust, suf
Some interesting design decisions:
Some interesting design decisions:
- A *block* of statements is sequence of `;` separated statements followed by an optional trailing statement. `Block` accepts a sequence of statements `StmtSeq*` followed by an optional trailing `Stmt`. `StmtSeq` is either a `Stmt``;`, or a `StmtBlock`, where the latter cover the case of `while`, `if` and `Block` (nesting/scopes) (without requiring `;` delimiting). We also see that `Stmt` accepts additional `;`. `Stmt` also accepts `ExprNoBlock`.
- A *block* of statements is sequence of `;` separated statements followed by an optional trailing statement. `Block` accepts a sequence of statements `StmtSeq*` followed by an optional trailing `Stmt`. `StmtSeq` is either a `Stmt``;`, or a `StmtBlock`, where the latter cover the case of `while`, `if` and `Block` (nesting/scopes) (without requiring `;` delimiting). We also see that `Stmt` accepts additional `;`. `Stmt` also accepts `ExprNoBlock` (which is essentially plain expressions, free of block constructs as further discussed below.)
``` Rust
``` Rust
Block: () = {
Block: () = {
...
@@ -80,12 +80,43 @@ Stmt: () = {
...
@@ -80,12 +80,43 @@ Stmt: () = {
- We treat statements that may be considered as expressions by a special rule `ExprBlock`, where we accept either `if then else` or a `block` (statments). (This is where we likely add `match` and similar statements later.)
- We treat statements that may be considered as expressions by a special rule `ExprBlock`, where we accept either `if then else` or a `block` (statments). (This is where we likely add `match` and similar statements later.)
Recall that a statement can be a return value, thus must somehow accept an expression. Now, here is the crux, since we want `if then else` and `blocks` (statements) to be treated as expression for assignments, it would cause ambiguities between statements as part of an expression or inside a *block*. We can resolve this by the adopting `ExprNoBlock`, inside of `stmt`. `ExprNoBlock` accepts expression besides those that are matched by `ExprBlock` (`if then else` and `block`).
Recall that a statement can be a return value, thus must somehow accept an expression. Now, here is the crux, since we want `if then else` and `block` (statements) to be treated as expression for assignments, it would cause ambiguities between statements as part of an expression or inside a *block*. We can resolve this by the adopting `ExprNoBlock`, inside of `stmt`. `ExprNoBlock` accepts expression besides those that are matched by `ExprBlock` (`if then else` and `block`).
-`;` is treated as a `stmt`, hence we accept *blocks* like `{; let a = 5;;;;; let b = 6;;; c}`. Notice, `;` carries no meaning besides for the optional trailing `;` of a *block* (determining the return type).
-`;` is treated as a `stmt`, hence we accept *blocks* like `{; let a = 5;;;;; let b = 6;;; c}`. Notice, `;` carries no meaning besides for the optional trailing `;` of a *block* (determining the return type).
-`"let" ExprNoBlock "=" Expr ";"`, forces a trailing `;` to each assignment (along the lines of the behavior of the Rust compiler).
## Reflection
``` Rust
Expr: () = {
ExprBlock,
ExprNoBlock,
}
ExprBlock: () = {
"if" ExprNoBlock Block "else" Block,
Block,
}
// Lowest Precedence
ExprNoBlock = Tier2<AndOrOp, AndOr>;
AndOr = Tier2<ComparisonOp, AddSub>;
AddSub = Tier2<AddSubOp, MulDiv>;
MulDiv = Tier2<MulDivOp, Unary>;
Unary = Tier1<UnaryOp, Term>;
// Highest Precedence
Term: () = {
Id,
Num,
Id "(" CommaNoTrail<Expr> ")",
"(" Expr ")",
}
...
```
-`Expr` accepts both `ExprBlock` (statements with return value), and plain plain expressions (`ExprNoBlock`).
- Precedences go from low to high, with `Term` having the highest precedence (matched first in a bottom up (LR) parser).
## Reflection on the Rust syntax
The Rust syntax seems somewhat arbitrarily chosen. The requirement that `let` statements must be trailed by `;`, is to my best understanding not required for soundness (the `let` could have been given a `Unit` type, similar to an assignment). This leads me to believe that the trailing `;` is rather an enforcement of style.
The Rust syntax seems somewhat arbitrarily chosen. The requirement that `let` statements must be trailed by `;`, is to my best understanding not required for soundness (the `let` could have been given a `Unit` type, similar to an assignment). This leads me to believe that the trailing `;` is rather an enforcement of style.